JEE Main 2019 Exam | Check All Details Regarding Mode & Type of Examination (CBT Mode)

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JEE Main 2019 Exam: On 1st September 2018, the application form filling for the JEE (Joint Entrance Exam) 2019 First Attempt has started on the NTA (National Testing Agency) website. Candidates can fill their application form on the official website on or before the 30th September. From next year, NTA will conduct the JEE Main exam and the exam will be conducted twice as JEE Main First Attempt and JEE Main 2nd Attempt. Here are the details regarding the Mode and Type of Examination.

JEE Main Exam 2019 Mode of Examination: The Joint Entrance Exam 2019 will be conducted in two papers and in CBT (Computer Based Test). The Paper 1 is for the admissions in the courses of B.E/BTech and the Paper 2 is for the admission in the B.Arch/B.Planning. The Mathematics Section Part 1 and the Aptitude test part II will be conducted in the CBT while the Drawing test will be conducted in Pen and Paper mode.

Type of Examination: As said above the Paper 1 will be conducted in the online mode. In the Paper 1 of the JEE Main Exam, there will be questions based on the subjects – Mathematics, Physics and Chemistry. All questions will be objective type MCQ. All the questions of the Paper 1 will have equal weightage.

The Paper 2 of the JEE Main Exam 2019 will be for the B.Arch & B.Planning course. In this paper, there will be three subjects. The questions in the Paper 2 will be from Mathematics Part I, Aptitude Test Part II and Drawing Test Part III. The Part 1 and Part 2 will be conducted via online mode while the Drawing test will be conducted offline. Mathematics and Aptitude section will have MCQ questions.

JEE Main 2019 Exam Date

The National Testing Agency will conduct the Joint Entrance Exam First Attempt from 6th January 2019 to 20th January 2018. The first shift of the exam will begin at 9:30 am and will end at 12:30. The duration of the shift is 3 hours. The entry in the examination hall for the first shift will start at 7:30 am to 8:30 am. Entry in the examination hall will be from 8:45 am to 9:00 am.

The second shift of the JEE Main Exam 2019 will begin at 2:30 pm and will end at 5:30 pm. The entry in the examination center for the second shift will be from 12:30 pm to 1:30. The entry to the examination hall will begin from 1:45 pm to 2:00 pm.

Source : chandigarhmetro

Resonance Eduventures Ltd. A premiere coaching institute in the field of Engineering, Medical, Commerce and Law.

ResoNite Pawan Goyal, maintaining the league, secures AIR 6 with highest marks 350/360 in JEE (Main) 2018.

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NTA Practice Centre Registration For UGC NET Exam 2018, JEE Main Exam 2019 & Other Exams Started on Official Website

nta-practice-centre-registration-for-ugc-net-exam-2018-jee-main-exam-2019-other-exams-started-on-official-website

With the starting of the online application process for the JEE Main Exam 2019 and UGC NET December 2018 exam, the National testing Agency has also started the online registration process for the NTA Practice Centre for the National Level Exams. The candidates who are interested can register themselves on the official website for the Practice Centres. Here are the details regarding the NTA Practice Centres. Check it out.

The NTA has started the process of application or registration for the Practice Centers from 1st September 2018. Candidates who are preparing for the UGC NET Exam, JEE Main, NEET, GPAT & CMAT can head over to the official website and register themselves there. NTA has also started the application form filling process for the JEE Main First Attempt 2019 and 2nd UGC NET Exam 2018. Here are the steps to apply or register for the NTA Practice Centre.

In order to register for the free Mock tests, candidates will have to go to the official website of NTA. The official website of NTA is https://nta.ac.in. Now on the home page of the website click on the Student registration (For Mock test). A new window will be open in front of you. Now select any method with which you want to log in.

Candidates can select this via email, login with Facebook or via mobile number. If the candidates will select mobile number, then they will have to enter the mobile number and then press the submit button. An OTP will be sent on the number. Enter that OTP on the screen. After that, a new window will be open and here candidates will have to enter all the required details.

Candidates will have to enter Name, Father Name, Date of Birth, Age, State, District, City, and Education qualifications. The candidates will also have to upload photograph and ID proof. Fill all details and register yourself.

The process of filling the online application form for the UGC NET 2018 exam and JEE Main exam 2019 has started online on the official website of NTA from 1st September 2018. The last date to apply for the JEE Main and UGC NET is 30th September. The last date for the payment of application fee is 1st October. The candidates are advised to fill their application form on or before the last date.

Source : chandigarhmetro

Resonance Eduventures Ltd. A premiere coaching institute in the field of Engineering, Medical, Commerce and Law.

ResoNite Pawan Goyal, maintaining the league, secures AIR 6 with highest marks 350/360 in JEE (Main) 2018.

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Admission open for Academic Session 2019-20 for class 5th to 12th. To Apply now, click here 

JEE Main merit list to be based on percentile scores

Joint Entrance Examination-Main (JEE-Main) 2019 merit list for admission to IITs and other engineering colleges will be based on percentile scores and not on marks. The percentile score to be used for the JEE Main will be based on the format adopted in NEET – Undergraduate MBBS entrance test.

JEE Main is the qualifying exam for the aspirants of JEE (Advanced) conducted for admission to Indian Institutes of Technology (IITs). The score in JEE Main is also considered by NITs, IIITs and various other CFTIs (Centrally Funded Technical Institutions) across the country for admission to their undergraduate programmes.

In addition to this, starting 2019, the JEE (Main) will be conducted by National Testing Agency (NTA). Previously, it used to be conducted by the Central Board of Secondary Education (CBSE). Aspirants can now appear for the exam twice in a year. JEE (Main) tests to be held in January and April in multiple sessions from next year.

Ranking and Marking Process for JEE Main

  • All sessions will have its own NTA percentile score with the highest score as 100 percentile
  • An overall NTA score will be prepared by including the scores of all the sessions for a final ranking
  • The top-ranked candidate in the final ranking will be the 100 percentile
  • The tie-breaker in between any percentile rank will be the highest percentile in mathematics, physics and chemistry in that order
  • If scores are tied even after this, the older person will be ranked higher
  • Final merit list will be announced after JEE Main-II exam
  • For candidates who take both the cycles of the exam, the better percentile will be count in the final merit list
  • There is no change in pattern and difficulty level of test, candidates will have different questions

Source : eletsonline

Resonance Eduventures Ltd. A premiere coaching institute in the field of Engineering, Medical, Commerce and Law.

ResoNite Pawan Goyal, maintaining the league, secures AIR 6 with highest marks 350/360 in JEE (Main) 2018.

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Admission open for Academic Session 2019-20 for class 5th to 12th. To Apply now, click here 

JEE Main merit list to be based on percentile scores from next year

JEE-MAIN-2019--MERIT-LIST-TO-BE-BASED-ON-PERCENTILE-SCORES

Yet another big news for JEE Main aspirants. News has poured in that the merit list for admission to engineering colleges, including Indian Institutes of Technology, through the Joint Entrance Examination – Main (JEE-Main) will be based on percentile scores and not the raw marks aspirants scored in the test, with the introduction of a two-cycle computer-based examination system from 2019. The NTA has introduced the normalisation of marks for the admission in engineering colleges. JEE Main is the entrance examination which acts as an eligibility test for those who wants to sit for JEE (Advanced) in order to take admission to IITs. As the format for architectural and engineering courses has changed with tests to be held in January and April, the National Testing Agency (NTA) reported another strategy for touching base at the NTA score, which will be the final merit list for admissions in IITs.

A senior official of the HRD ministry stated that the “normalisation procedure based on percentile score” to arrive at the NTA score has been based on the format in practice for the undergraduate-MBBS test conducted by the All India Institute of Medical Sciences, Delhi. The official added, “A core group of experts from IITs (Roorkee, Kanpur, Delhi, Guwahati), IIM-Lucknow, NITs, UGC, IASRI (Pusa) and AIIMS, Delhi, among others have been asked to finalise the process for calculating the NTA score.”

From next year onward, a JEE-Main aspirant will have the choice of attempting the test two times, during the January and the April cycles. Each test cycle will have 14 days with multiple sessions each day. An NTA official explained the format saying, “Candidates will get different sets of questions per session and though efforts will be made to maintain equivalence among various question papers, the difficulty level of question papers in different sessions may not exactly be same.” Therefore, the prospects of cheating and manipulation are comparatively lesser now.

About NTA

The National Testing Agency also known as NTA has been established as an autonomous and self-sustained testing body to conduct entrance examinations for admission/fellowship in higher educational institutions. This year the NTA will be conducting engineering, medical as well as management courses. JEE Main 2019, NEET 2019, CMAT 2019 and UGC NET examination are some of the competitive examinations that NTA will focus on.

Source : jagranjosh

Resonance Eduventures Ltd. A premiere coaching institute in the field of Engineering, Medical, Commerce and Law.

ResoNite Pawan Goyal, maintaining the league, secures AIR 6 with highest marks 350/360 in JEE (Main) 2018.

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Admission open for Academic Session 2019-20 for class 5th to 12th. To Apply now, click here 

JEE (Main) merit list will be based on percentile score; details inside

National-Test-Agency

From 2019, the merit list for admission to IITs and other engineering colleges through Joint Entrance Examination-Main (JEE-Main) will be based on percentile scores and not based on marks. Apparently, the percentile score to be used for the exam will be based on the format used for the undergraduate MBBS test.

is the qualifying exam for those intending to sit for JEE (Advanced) in order to seek admission in undergraduate programmes in IITs, NITs, IIITs and various other CFTIs (Centrally Funded Technical Institutions) across the country.

In addition to this, starting 2019, the will be conducted by National Testing Agency (NTA). Previously, CBSE used to conduct the test. A JEE-aspirant will now have a choice to sit for the exam twice in a year.

The tests to be held in January and April in multiple sessions from next year.

PROCESS OF RANKING & MARKING FOR JEE-MAIN

All sessions will have its own NTA percentile score with the highest score as 100 percentile.

  • An overall NTA score will be prepared by including the scores of all the sessions for a final ranking according to Times of India.
  • The top-ranked candidate in the final ranking will be the 100 percentile.
  • The tie-breaker in between any percentile rank will be the highest percentile in mathematics, physics and chemistry in that order.
  • If scores are tied even after this, the older person will be ranked higher.
  • Final merit list will be announced after 2
  • For candidates who take both the cycles of the exam, the better percentile will be count in the final merit list.
  • There is no change in pattern and difficulty level of test, candidates will have different questions.

“Normalisation procedure based on percentile score” to arrive at the NTA score, a senior official from HRD ministry told Times of India.

Source : business-standard

Resonance Eduventures Ltd. A premiere coaching institute in the field of Engineering, Medical, Commerce and Law.

ResoNite Pawan Goyal, maintaining the league, secures AIR 6 with highest marks 350/360 in JEE (Main) 2018.

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Admission open for Academic Session 2019-20 for class 5th to 12th. To Apply now, click here 

JEE Main 2019: NTA releases application form on official websites

The National Test Agency has released application forms for the Joint Entrance Examination (JEE) Main 2019 on the official websites nta.ac.in and jeemain.nic.in.

According to the notification, the candidates can apply between September 1 and September 30. The last date to submit the fee is October 1.

The JEE (Main) will be conducted twice a year and from the next academic session in 2019.

The first JEE (Main) has been scheduled from 6 to 20 January, 2019 for candidates seeking admission to undergraduate progammes in NITs, IITs and other centrally funded Technical institutions.

The timings for the JEE (Main) 1 are divided into two shifts. Candidates can give exam in either of the following shifts: From 9:30 am to 12:30 pm, or from 2:30 pm to 5:30 pm. The exam will be in computer based test (CBT) mode only. The key subjects are mathematics, physics and chemistry.

JEE (Main) paper 2 is to be given by Bachelor of architecture (B Arch) aspirants and Bachelor of Planning ( B. Planning) aspirants, in one sitting only. This test will be conducted from April 6, 2019 to April 20th, 2019. This exam will be held in a single shift only. Part 1 and part 2 will be mathematics and aptitude test and part 3 will be a drawing test.

Admission to IITs will be based only on category-wise All India Rank in JEE (Advanced), subject to condition mentioned on JEE(Advanced) website.

Candidates needn’t appear for both the JEE (Main) tests. However, if a candidate appears in both the tests, the better of the two scores will be used for the eligibility for JEE (Advance) 2019.

IMPORTANT DATES:

JEE (MAIN) 1:

  • Online submission of application forms: Sept 1 to Sept 30, 2018.
  • Admit card download: December 17, 2018
  • Examination date: Jan 6 to Jan 20, 2019 (Candidate can choose any one out of the eight sittings).
  • Result declaration: January 31st, 2019.

JEE (Main) 2:

  • Online submission of application form: February 8 to March 7, 2019.
  • Admit card downloading 18 March 2019.
  • Examination date: From April 6, 2019 yo April 20, 019. (Candidates can choose only one sitting out of the eight sittings)
  • Results declaration: April 30, 2019.

Eligibility criteria

JEE (Main) is applicable for those candidates who have secured at least 75% marks in the 12th class examination, or be in the top 20 percentile in the 12th class examination conducted by the respective Boards.

For SC/ST candidates the qualifying marks would be 65% in the 12th class examination.

Source : business-standard

Resonance Eduventures Ltd. A premiere coaching institute in the field of Engineering, Medical, Commerce and Law.

ResoNite Pawan Goyal, maintaining the league, secures AIR 6 with highest marks 350/360 in JEE (Main) 2018.

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Admission open for Academic Session 2019-20 for class 5th to 12th. To Apply now, click here 

 

No more confusion in JEE main attempts limit; confirms NTA

iit-jee

Since when the Union Ministry of the Human Resource and Development (HRD) has allocated the National Testing Agency (NTA) with the charge of conducting the JEE Main, there have been many speculations about the maximum number of permissible attempts for the candidates. Clearing all the doubts, NTA has recently declared that there will not be any restriction on the maximum number of allowed attempts for JEE Main.

However, the candidates will have to satisfy all the requirements as per the eligibility criteria. For instance, only those candidates will be able to appear in one or both sessions of the JEE Main 2019 exam, who either had qualified their class 12th examination in 2017/2018 or are going to appear for the same in 2019.

Beyond that, those aspirants who either passed their 12th class in 2016 or are going to appear in the same in 2020 will be ineligible for JEE Main 2019. Till 2018, candidates could appear in the JEE Main examination for a maximum of three times in total. With the transfer of responsibility for conducting the JEE Main exam from the Central Board of Secondary Education (CBSE) to NTA, many new changes were introduced.

When it was announced that JEE Main 2019 will be conducted in two sessions i.e. in January 2019 and April 2019, the aspirants were concerned to know if some changes would also be introduced about the maximum number of attempts that they would get to appear in the examination. Especially those aspirants, who would already have appeared in the JEE Main exam twice earlier in 2017 and 2018, were dubious about their eligibility for appearing in both the sessions of JEE Main 2019.

In case the previous criteria of a maximum number of three permissible attempts would have retained, such candidates would be able to attempt only the Session I of JEE Main 2019. Post then, they were supposed to be ineligible for appearing in the Session II, since their maximum limit of number of attempts (three) was going to be exhausted.

However, NTA has recently released a detailed notification along with an information brochure for the aspirants of JEE Main 2019. Candidates will be able to access and download the JEE Main 2019 information brochure through the official website of NTA – nta.ac.in.

Other than removing the cap from the maximum number of attempts for JEE Main, the age limit criterion has also been removed for appearing in the JEE Main 2019 exam. Till 2018, there was a specified duration in which the birth date of the candidate must have been fallen to be eligible for the registration of the JEE Main and JEE Advanced exams.

Going forward, the aspirants of any age group could register for JEE Main, unless they satisfy the other specified requirements. As per the statement in the JEE Main 2019 information brochure, “Irrespective of the number of JEE Main attempts candidates have taken, they can apply for the upcoming JEE Main 2019 if they satisfy the eligibility criteria. Candidates who did their class 12th in 2016 or will be enrolled for Boards 2020 are not eligible.”

As per another requirement, the candidates will have to pass their 12th class examination in five subjects. Additionally, those candidates who would have passed their 12th class from the commerce stream will not be eligible for appearing in the Paper 1 of JEE Main 2019 (for the B.Tech. courses), as per the requirements specified by the IIITs, NITs and GFTIs.

Apart from that, the aspirants of Paper 1 must have one of the Chemistry, Biotechnology, Biology or a Technical Vocational subject, alongside Physics and Mathematics as the mandatory subjects. For appearing in the Paper 2 of JEE Main 2019 (for the B.Arch. and B.Plan. courses), students must have passed the 12th class examinations with Mathematics as a core subject.

As stated in the information brochure issued by NTA, since all the papers of JEE Main 2019 will be conducted in the online mode, the Mathematics and Aptitude sections of Paper 2 will be computer-based. However, candidates will be required to undergo the drawing test on a drawing sheet.

The eligibility criteria for both the sessions of JEE Main 2019 will be kept same. Other than defining the eligibility criteria, the information brochure describes the registration and application process of JEE Main 2019 and other important information. Candidates are suggested to thoroughly go through the eligibility criteria specified in the information brochure to avoid the late stage cancellation of their registration.

Source : yovizag

Resonance Eduventures Ltd. A premiere coaching institute in the field of Engineering, Medical, Commerce and Law.

ResoNite Pawan Goyal, maintaining the league, secures AIR 6 with highest marks 350/360 in JEE (Main) 2018.

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Admission open for Academic Session 2019-20 for class 5th to 12th. To Apply now, click here